Red Black Trees implemented in Haskell.
Red Black Tree data structure implemented in Haskell. The goal of this project is to provide an efficient generic structure that can insert and find elements in O(log(n)) time.
red-black-tree
Red Black Tree data structure implemented in Haskell.
The goal of this project is to provide an efficient generic structure that can insert and find elements in O(log(n)) time.
Usage
Implement BinaryTreeNode
To insert values to a RedBlackTree
, their type must have an instance of BinaryTreeNode
. Members of this typeclass must implement Ord
, and consequently Eq
, so that values can be compared and sorted within the tree. Since inserting duplicate values can corrupt the tree, this typeclass provides the following function:
mergeNodes :: a -> a -> a
This function takes two BinaryTreeNode
values and returns a new "merged" node. It is only called when a value is about to be inserted, but the tree already contains another value that is equal to it. This new "merged" node replaces the existing one without doing any further modifications to the tree.
If you want to ignore duplicate nodes, you can just return the first parameter, since that one is guaranteed to be the one that is already in the tree, whereas the second parameter is the node that we are are trying to insert. On the other hand, if you want to replace older nodes with newer ones then you can return the second parameter. If your use case is completely different then you can create a new node with the best parts from each node and return that. Implementing mergeNodes
is all you need to do to get a working BinaryTreeNode
instance.
The API
To use this data structure you only need to know about these three functions exposed by the Data.RedBlackTree
module:
emptyRedBlackTree :: RedBlackTree a
insert :: (BinaryTreeNode a) => RedBlackTree a -> a -> RedBlackTree a
find :: (BinaryTreeNode a) => RedBlackTree a -> a -> Maybe a
emptyRedBlackTree
is pretty self explanatory, you can use this as a constructor.
insert
takes an existing tree and a new value and returns a new tree that contains the new value.
find
takes an existing tree and a target value and returns the value inside that tree that is equal to the target. Returns Nothing
if no such value is found.
Example
Suppose we wanted to store our app's users on a RedBlackTree
. For simplicity, let's assume that we only know two things about the user: the user's email address, a string guaranteed to be unique for each user, and the user's name. The type User
could look like this:
data User = User {
userEmail :: String,
userName :: String
} deriving Show
Since e-mail adresses are guaranteed to be unique, we don't care about duplicates so the User
instances for Eq
, Ord
and BinaryTreeNode
would look like this:
instance Eq User where
(==) leftNode rightNode = userEmail leftNode == userEmail rightNode
instance Ord User where
(<=) leftNode rightNode = userEmail leftNode <= userEmail rightNode
instance BinaryTreeNode User where
mergeNodes leftNode _ = leftNode
The final step is to write a small program that inserts 8 users, and then looks up the name of the user whose address is "[email protected]".
import Data.List (foldl')
import Data.RedBlackTree
import Data.User -- This module defines our User type
main = do
-- create users to insert
let users = [
User "[email protected]" "Gabriel",
User "[email protected]" "Jimmy",
User "[email protected]" "Paul",
User "[email protected]" "George",
User "[email protected]" "Frank",
User "[email protected]" "David",
User "[email protected]" "Bryan",
User "[email protected]" "John"
]
-- insert one by one
let treeWithOneUser = insert emptyRedBlackTree (User "[email protected]" "gabriel")
let treeWithTwoUsers = insert treeWithOneUser (User "[email protected]" "jimmy")
-- insert the whole list with foldl'
let userTree = foldl' insert emptyRedBlackTree users
-- find the username with address "[email protected]". The Eq instance of User only
-- checks for email address, so we can leave the username empty in the target value
let targetNode1 = User "[email protected]" ""
print $ fmap userName (find userTree targetNode1)
-- should print "Just frank"
-- find the username with address "[email protected]"
let targetNode2 = User "[email protected]" ""
print $ fmap userName (find userTree targetNode2)
-- should print Nothing
Limitations
Currently the only operations supported are find
and insert
. There is no remove
at the moment.
Development
To build this library, clone this repo and use Stack.
git clone https://github.com/GAumala/red-black-tree
stack setup
stack build
To run unit tests with RSpec:
stack test